Open excel file in Python: XLRDError: Excel xlsx file; not supported

Question

I want to open an Excel file in Python, using:

import xlrd

loc = (r"C:\Users\my_path\my_file.xlsx")

wb = xlrd.open_workbook(loc)
sheet = wb.sheet_by_index(0)
sheet.cell_value(0, 0)

and it caught error:

---------------------------------------------------------------------------
XLRDError                                 Traceback (most recent call last)
<ipython-input-70-b399ced4986e> in <module>
      4 loc = (r"C:\Users\my_path\my_file.xlsx")
      5 
----> 6 wb = xlrd.open_workbook(loc)
      7 sheet = wb.sheet_by_index(0)
      8 sheet.cell_value(0, 0)

C:\Python38\lib\site-packages\xlrd\__init__.py in open_workbook(filename, logfile, verbosity, use_mmap, file_contents, encoding_override, formatting_info, on_demand, ragged_rows, ignore_workbook_corruption)
    168     # files that xlrd can parse don't start with the expected signature.
    169     if file_format and file_format != 'xls':
--> 170         raise XLRDError(FILE_FORMAT_DESCRIPTIONS[file_format]+'; not supported')
    171 
    172     bk = open_workbook_xls(

XLRDError: Excel xlsx file; not supported

What is wrong?

Answer 1

The lastest version of xlrd is only support.xls file, so you can install the older version

pip uninstall xlrd pip install xlrd==1.2.0

Answer 2

Or you can use the openpyxl to do it.

pip install openpyxl

If you use it in Pandas:

import pandas as pd
pd.read_excel('file/path/to/excel/spreadsheet.xlsx', engine='openpyxl')

If you don't specify the engine, it will use whatever default.