I have this struct
typedef struct tournament_t
{
Map players;
}*Tournament;
the Map Adt used in the struct is generic and uses this typedef for void*
/** Data element data type for map container */
typedef void *MapDataElement;
I want a Copy Function for the Tournament struct and it has to be with type MapDataElement
so this is the function
MapDataElement tournamentCopy(MapDataElement tournament)
{
//some code
Tournament ptr = *(Tournament*)tournament;
copy->players=mapCopy(ptr->players);
//some code
}
the problem is that no matter what i do ptr->players
is always null when I tried to change the type that the function gets from MapDataElement
to Tournament
everything worked fine, However I am not allowed to change it so... any ideas?
You have pointer confusion. Use:
typedef struct tournament_t
{
Map players;
}Tournament;
typedef struct mapdataelement_t
{
// definition
} MapDataElement;
and now:
MapDataElement *tournamentCopy(MapDataElement *tournament)
{
Tournament *ptr = (Tournament *)tournament;
The root of all your problems is trying to hide pointers behind typedefs which makes the code needlessly complex and unreadable - you are only creating a bunch of problems for yourself with this.
Simply do:
typedef struct
{
Map players;
} tournament_t;
I want a Copy Function for the Tournament struct and it has to be with type MapDataElement
Ok so make MapDataElement
something that makes sense, void*
probably does not. If you want it to be some sort of generic item container then typedef it as such:
typedef struct
{
void* data;
size_t size;
// whatever makes sense to include here, an enum to list types perhaps?
} MapDataElement;
And finally, modern C allows you to do type safe, type-generic programming without dangerous void pointers:
#define something_copy(x) _Generic((x), \
tournament_t: tournament_copy, \
thingie_t: thingie_copy) (x)
This means that the function-like macro "something_copy" will call the relevant specific function based on the type passed. Or if you pass a wrong type not supported - a compiler error.
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