This the code, I need to access the second <p>
element using javascript, I have tried many things unable to access it. Please help me on this
<div class="demo">
<div>
<p>Some Text...</p>
<p><b>Author:</b> Author Name</p>
<p>Some Text...</p>
</div>
</div>
You can use getElementsByTagName()
and get the second element in the list.
const secondP = document.getElementsByTagName("p")[1];
you can get element by their tag name check this documentation: https://developer.mozilla.org/en-US/docs/Web/API/Document/getElementsByTagName
const allParas = document.getElementsByTagName('p'); // collection of all p tags
allParas[1]; // sencond p tag
You can select the second p
tag using nth-child
. I have colored the text red, for demonstration purposes.
let p = document.querySelector(".demo div p:nth-child(2)") p.style.color = "red";
<div class="demo"> <div> <p>Some Text... </p> <p><b>Author:</b> Author Name </p> <p>Some Text... </p> </div> </div>
As shown in the accepted answer you can safely use the nth-child(n)
selector however that's perhaps more suitable for dynamically accessing the n
'th child. Such as;
var n = 2;
document.querySelector(`.demo div p:nth-child(${n})`);
On the other hand CSS selector combinators are also very powerful. If you simply want to access the very next <p>
coming after the first <p>
which is directly under a <div>
which is directly under an element with .demo
class. So ".demo > div > p + p"
should be sufficient. In this particular case we don't have any nested div
s under .demo
so we can also do like ".demo div p + p"
.
var el = document.querySelector(".demo > div > p + p"); console.log(el.textContent)
<div class="demo"> <div> <p>Some Text...</p> <p><b>Author:</b> Author Name</p> <p>Some Text...</p> </div> </div>
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