how to extract data in paragraph using regex

Question

Customer Reference N139211508474572 Entry Date 05/19/2021 Extra Information NEFT IN UTR FROM S S DISTRIBUTOR N139211508474 572TXN REF NO 23621001323

How can I extract the vender company name like SS DISTRIBUTOR, In this FROM is constant in multiple data I have, I did the regex code to extract customer reference number(?<=Customer Reference ).+(?= Entry Date) like this it's working, and give me a code to extract the vender company name.

The customer reference number is not constant it will have mixed numbers and alphabets or only numbers.

Answer 1

Assuming the vender company name is located between the keyword FROM and the customer reference number, would you please try:

Customer Reference (.*).* FROM (.*) \1

The Group2 captures the vendor company name SS DISTRIBUTOR .

Demo

Answer 2

You didn't specify what language you were actually using, and as @some-programmer-dude mentioned regex is not necessarily the best solution for searching in a string.

You tagged python so assuming that is what you are using, you can consider using split and index to get whatever is after FROM and 2 words before REF :

s = "Customer Reference N139211508474572 Entry Date 05/19/2021 Extra Information NEFT IN UTR FROM S S DISTRIBUTOR N139211508474 572TXN REF NO 23621001323"
# Convert all to UPPER case first
s = s.upper()
# Clean unnecessary whitespaces first just in case
s = " ".join(s.split())
# Get all text after FROM
s = s.split("FROM")[1]
# Get all text which are 2 words before REF
index_of_REF = s.split().index("REF")
s = " ".join(s.split()[:index_of_REF-2])
print(s)

This gives:

S S DISTRIBUTOR