So I have a column of strings of numbers in which certain cells have words ahead of the strings. It looks a little something like this:
Names | Values |
---|---|
First | '9.90' |
Second | '9.68' |
Third | '9.45' |
Fourth | 'Loan fee:8.10' |
Fifth | '9.98' |
Now I've tried a lot of different ideas just to get the 'Loan fee:' removed, basically i first converted it into a list called newz and then tried
e=[]
for i in newz:
i.replace('Loan fee:','')
e.append(i)
Tried using regex as well:
def change(i):
re.sub('Loan fee:','',i)
result = list(map(lambda x: change(x),newz))
So far nothing's worked
If you're using Pandas:
import pandas as pd
df = pd.DataFrame({
'Names': ['First', 'Second', 'Third', 'Fourth', 'Fifth'],
'Values': ['9.90', '9.68', '9.45', 'Loan fee:8.10', '9.98']
})
df['Values'] = df['Values'].str.replace('Loan fee:', '')
print(df)
Outputs
Names Values
0 First 9.90
1 Second 9.68
2 Third 9.45
3 Fourth 8.10
4 Fifth 9.98
str.replace
returns a new string. Also you should first check whether the string contains 'Loan fee:' and then replace it.
So you should do:
e=[]
for i in newz:
if "Loan fee:" in i:
s = i.replace('Loan fee:','')
e.append(s)
else:
e.append(i)
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