How to return render_template in Flask?
Question
The following code works perfectly from the .py file but I want to separate the HTML and put it in templates/index.html.
I suppose I have to use the render_template function in Flask to be able to return the same results.
# File dynamic_website.py
from owlready2 import *
onto = get_ontology("bacteria.owl").load()
from flask import Flask, url_for
app = Flask(__name__)
@app.route('/')
def ontology_page():
html = """<html><body>"""
html += """<h2>'%s' ontology</h2>""" % onto.base_iri
html += """<h3>Root classes</h3>"""
for Class in Thing.subclasses():
html += """<p><a href="%s">%s</a></p>""" % (url_for("class_page", iri = Class.iri), Class.name)
html += """</body></html>"""
return html
I created a folder template and a file index.html. I used return render_template('index.html') but it doesn't work. What arguments do I have to add to the return_template function? "for Class in Thing.subclasses():" have to be in the .html file or .py file? What about the url_for function?
If you could edit the .py code and let me know what should I write exactly in the index.html file to have the same results it would be great.
UPDATE:
What I have done:
from flask import Flask, render_template
from owlready2 import *
from flask import Flask, url_for
onto = get_ontology("bacteria.owl").load()
app = Flask(__name__)
@app.route("/")
def ontology_page():
for Class in Thing.subclasses():
return render_template('index.html')
<!DOCTYPE html>
<html lang="en" dir="ltr">
<head>
<meta charset="utf-8">
<title></title>
</head>
<body>
<h1>{{ Class.name }}</h1>
</body>
</html>
1 answers
solution1
1 2021-07-18 13:56:51
You can't send return something multiple times.
If you want the user to see a list of things on the html, do this. render_template('index.html', things=Thing.Subclasses()) This will give Jinja a list, where it can then for loop.
For html you can do this {% for s in things %} {{ s }} is something {% endfor %} . Do anything you want with the s though, s is one subclass from the list.
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