Lambda not working even when the condition is satisfied in python

Question

I want to print 1 if the word is in the paragraph, if not then print 0

The first line contains the word bestselling yet lambda is printing 0

Answer 1

A good way to do that is to use any function and cast to int the result.

text = "this is a text used for an example."

first_list = ["word", "second_word", "example"]
second_list = ["word", "second_word", "third_word"]

is_in = int(any(k in text for k in first_list))
print(is_in) # print 1

not_in = int(any(k in text for k in second_list))
print(not_in) # print 0

Answer 2

A way to search in a DataFrame would be using the contains method of str (documentation here) . In your case you want to search whether multiple words are in the text, so a regular expression could be used:

df["sun"][0].str.contains("brilliant|bestselling|best|best-selling|loved|great|amazing", regex=True)

If you also want to match the word regardless of if it's in lowercase or uppercase you can add:

import re
df["sun"][0].str.contains("brilliant|bestselling|best|best-selling|loved|great|amazing", flags=re.IGNORECASE, regex=True)