I've made the following declarations on my code:
char bussola, com[1], pen;
int main()
{
bussola = "oeste", pen = "up";
but for some reason I'm getting this error on the compiler:
main.c:18:10: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
bussola = "oeste", pen = "up";
^ ^
And because of that I keep getting other errors like this one:
main.c:51:17: warning: comparison between pointer and integer
if (bussola == "oeste")
^~
What should I do?
you are assigning a char array (AKA string) to a char variable, they are't compatible data tipes. A char variable can only have single char values (like 'a' , 'F', '2' or ' '). Its important to use single quotes (' ') to interpret the character like a char variable. You can declare a string using char * bussola or char bussola[LENGTH], but you will have to inicialite the array in the declaration:
char bussola[6] = "oeste";
if you want to inicialite it later, you can use strcpy:
char bussola[6];
strncpy(bussola, "oeste", 6);
Be aware that string use doble quotes (" ") instead of single quotes like chars.
char bussola[6], pen[3];
int main() {
strcpy(bussola, "oeste");
strcpy(pen, "up");
}
if(!strcmp(bussola,"oeste")
This above is the correct syntax for what you are trying to do.
Considering this code, I would suggest to thorough the strings and character concepts in C and also the string.h
header file functions.
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.