Regular expression: to find limited iterations

Question

I need to find numbers in the given string and I need to extract first two numbers from the string. Ex., In second example I need to take 1536 and 678 but this code show the all the containg number.

import re
pattern = r"(\d{1,})"
match = re.findall(pattern, "123")
if match:
    print (match)
match = re.findall(pattern, "1536+678+ 888")
if match:
    print (match)    
match = re.match(pattern, "abc cde")
if match:
    print ("Match 3")

Answer 1

Take the first two from matched results:

print(match[:2])