I tried to use continue
in a while loop to skip print
number but it doesn't work.
num = int(input())
while int(num) > 0 :
num-=1
print(num)
if num == 6:
continue
elif num ==1:
print("8 Numbers Printed Successfully.")
break
#i want to remove number six
Try this
num = int(input())
while num > 0 :
num -= 1
if num == 6:
continue
elif num == 1:
print("8 Numbers Printed Successfully.")
break
print(num)
Your print line should be after the if-else block
num = int(input())
while int(num) > 0:
num -= 1
# print(num) => if you print here, it does not check the condition
if num == 6:
continue
elif num == 1:
print("8 Numbers Printed Successfully.")
break
# print number here
print(num)
First of all, how do you know it's been 8 numbers? The input can be any number. Secondly, if you want to print every number but 6
you need to move the num -= 1
too. Being there, it won't print the first number.
Try this if you don't insist on using continue
:
num = int(input())
printed_numbers = 0
while int(num) > 0 :
if num != 6:
print(num)
printed_numbers += 1
num -= 1
print("{} Numbers Printed Successfully.".format(printed_numbers))
Or this, if you want to test continue
:
num = int(input())
printed_numbers = 0
while int(num) > 0 :
if num == 6:
num -= 1
continue
print(num)
printed_numbers += 1
num -= 1
print("{} Numbers Printed Successfully.".format(printed_numbers))
Finally, If you're ok with the num -= 1
there:
num = int(input())
printed_numbers = 0
while int(num) > 0 :
num -= 1
if num == 6:
continue
print(num)
printed_numbers += 1
print("{} Numbers Printed Successfully.".format(printed_numbers))
NOTE : I'm using printed_numbers
because if
the input is less than 6
you will print all the numbers else
you'll have one less. You can use this condition instead.
You are print the number before the condition. chnage the code as follows.
num = int(input())
while int(num) > 0 :
num-=1
if num != 6:
print(num)
elif num == 1:
print("8 Numbers Printed Successfully.")
break
#i want to remove number six
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