Can anyone tell me what's the issue in this please? I am getting an error that "grep: c is not a file or directory". If do this same pattern for 1 pipe (2 commands), it works perfectly, However, if I do it with 2 pipes (3 commands), it stops working.
CAN ANYONE PLEASE TELL ME WHAT'S THE ISSUE IN THIS CODE?
int main(int argc, char** argv)
{
int pipefd[2];
int pipefd2[2];
char* cmd[3]={"ls",NULL,NULL};
char* cmd2[3]={"grep","c",NULL};
char* cmd3[3]={"wc", NULL, NULL};
pipe(pipefd);
pipe(pipefd2);
if(fork() == 0)
{
if(dup2(pipefd[1],1) < 0)
{
printf("Error in dup2\n");
exit(0);
}
close(pipefd2[0]);
close(pipefd2[1]);
close(pipefd[0]);
close(pipefd[1]);
if(execvp("ls", cmd) < 0)
{
printf("Error in execvp ls\n");
exit(0);
}
}
if(fork() == 0)
{
if(dup2(pipefd[0],0) < 0)
{
printf("Error in dup2\n");
exit(0);
}
if(dup2(pipefd2[1], 1) < 0)
{
printf("Error in dup2\n");
exit(0);
}
close(pipefd2[0]);
close(pipefd2[1]);
close(pipefd[0]);
close(pipefd[1]);
if(execvp("grep",cmd2) < 0)
{
printf("Error in execvp grep\n");
exit(0);
}
}
if(fork() == 0)
{
if(dup2(pipefd2[0],0) < 0)
{
printf("Error in dup2\n");
exit(0);
}
close(pipefd2[0]);
close(pipefd2[1]);
close(pipefd[0]);
close(pipefd[1]);
if(execvp("wc",cmd2) < 0)
{
printf("Error in execvp wc\n");
exit(0);
}
}
close(pipefd[0]);
close(pipefd[1]);
close(pipefd2[0]);
close(pipefd2[1]);
wait(NULL);
wait(NULL);
wait(NULL);
return 0;
}
This is caused by incorrect use of execvp.
The first argument is the file you wish to execute, and the second argument is an array of null-terminated strings that represent the appropriate arguments to the file.
Effectively, you are running grep grep c
in your shell. You can try it, and see that the same effect happens.
See the man page https://linux.die.net/man/3/execvp for further reading.
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