I would like to generate a 16 character code
The code has 5 known characters The code has 3 digits The code must be random
What I did:
result1 = "NAA3U" + ''.join((random.choice(string.ascii_uppercase + string.digits) for codenum in range(11)))
One approach:
import random
import string
# select 2 digits at random
digits = random.choices(string.digits, k=2)
# select 9 uppercase letters at random
letters = random.choices(string.ascii_uppercase, k=9)
# shuffle both letters + digits
sample = random.sample(digits + letters, 11)
result = "NAA3U" + ''.join(sample)
print(result)
Output from a sample run
NAA3U6MUGYRZ3DEX
If the code needs to contain at least 3 digits, but is not limited to this threshold, just change to this line:
# select 11 uppercase letters and digits at random
letters = random.choices(string.ascii_uppercase + string.digits, k=11)
this will pick at random from uppercase letters and digits.
You can add the remaining 2 digits at the end if it is fine for you like this
import random
import string
result1 = "NAA3U" + ''.join((random.choice(string.ascii_uppercase) for codenum in range(8))) + str(random.randint(10,99))
print(result1)
NAA3URYWMGIHG45
You can use random.choices
and random.shuffle
then use ''.join
like below:
>>> import random
>>> import string
>>> def generate_rndm():
... digit_char = random.choices(string.ascii_uppercase, k=9) + random.choices(string.digits, k=2)
... random.shuffle(digit_char)
... return "NAA3U" + ''.join(digit_char)
Output:
>>> generate_rndm()
'NAA3UTVQG8DT8NRM'
>>> generate_rndm()
'NAA3UCYBWCNQ45HR'
>>> generate_rndm()
'NAA3UIJP7W7DLOCQ'
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