I am new to coding. if user give wrong input how can we ask to reenter input without exiting code?

Question

My question is that when user gives wrong input it throw exception msg "wrong input" and exits the code. I want to ask again to enter the input without exiting code. I tried while loop but I didn't do it right, so please help with my doubt.

import java.util.Scanner;

public class A{

    public static void main(String[] args) {
      Scanner sc=new Scanner(System.in);
      
      try {  System.out.println("enter");
      int a=sc.nextInt();
      int b=sc.nextInt();
           System.out.println(a+b);
          
      } catch (Exception e) {
          //TODO: handle exception
          System.out.println("wrong input");
          System.out.println("enter again");
         
      }
   }
}

Answer 1

Use while loop and break.

while (true)
{
    try {
        System.out.println("enter");
        int a = sc.nextInt();
        int b = sc.nextInt();
        System.out.println(a + b);
        break;
       } catch (Exception e) {
            System.out.println("wrong input");
            System.out.println("enter again");
            sc.nextLine();
       }
}

Only when both a and b values are entered correctly, then it'll break out of while loop, otherwise it'll keep looping.