How to match a particular URL pattern in Python regex

Question

I am having trouble matching a pattern of this format: p#.g.com where # is not a 1 or a 2. For instance if the pattern is p1.g.com , I don't need to match. If it it p2.g.com , I don't need to match.

But if it is any other number, such as p3.g.com or p29.g.com , then I need to match.

My current pattern is r"(?P<url>p([^1,2])\\.g\\.com)" , but this fails if the pattern is p##.g.com, basically any two digit number it fails on. There is no upper limit on the #, so it could be a 3 or 999 or anything in between.

I also tried r"(?P<url>p([^1,2])\\d+\\.g\\.com)" but that does not match any number beginning with a 1 or a 2. For instance 11 or 23 are not matched, which I do want matched.

Answer 1

Try this regex:

p(?:[03-9]|\d{2,})\.g\.com

Demo

Explanation:

• Matches character p
• Start of non-capturing group
  • Match one of:
    • The digits 0 or 3-9
    • Any double digit number like 10 or higher
• Matches character .g.com