What is proper way to chain a future without transforming it?

Question

Suppose I have 2 functions that return a type of Future.

ListenableFuture<User> createUser();

CompletableFuture<BillingAccount> createBillingAccount(User user);

I need to run createUser() before running createBillingAccount because it depends on the user created.

However, I want to return the user, not the billingAccount.

Normally, I would use Futures.transformAsync(createUser(), user -> createBillingAccount(user)) but this would return a BillingAccount. I want to return a user.

What else can I do here without blocking?

Answer 1

您可以简单地执行未来，然后执行thenApplyAsync并返回用户，以便您返回用户的未来，并放弃计费，如下所示：

Futures.transformAsync(createUser(), user -> createBillingAccount(user).thenApplyAsync(b -> user))