Get latest duplicates based on a column sql powershell

Question

I have a table retrived from a sql query like below

   Id   Date-Time            FilesA    FilesB

   556  2020-10-13 21:12:04  temp1.txt fels.csv
   133  2020-09-08 03:22:16  NA        temp2.txt
   556  2020-10-13 22:02:44  temp1.txt fels.csv
   203  2021-08-03 03:22:16  macs.xml  temp2.txt

I'm pulling out FilesA and FilesB column and doing some operation for all Ids of Id column. But there are some duplicates in the Id column, I need to perform the operations only on the latest Id based on the Date-Time column like for 556 I need to work with FilesA and FilesB of the 3rd row as it is generated latest ie, on 22:02. I can have multiple duplicates of different Ids like this. How do I achieve that with powershell script? All I've found to identify duplicates is using csv which doesn't seem helpful here as I don't need csv and for the time date column is there anything like converting the retrieved column data to date time object and then compare? I'm lost.

$SqlAdapter.SelectCommand = $SqlCmd
$Dataset = New-Object System.Data.Dataset
$SqlAdapter.Fill($Dataset)
$DataSet.Tables[0]
$data1=$DataSet.Tables[0]
$data1.FilesA #some operations
#need to perfrom the actions on all ids and for duplicates only on the latest ones

Answer 1

Use Group-Object to group the rows by Id , then pick the one with the newest date from each group with Sort-Object -Descending |Select -First :

$newestRowPerId = $data1 |Group-Object Id |ForEach-Object { 
    $_.Group |Sort-Object -Property 'Date-Time' -Descending |Select -First 1 
}