Get row number from two dimensional array with double criteria in different column

Question

I have a 2 dimensional array like this:

     Name    ID    Date
0    Jhon     2      3
1    Elton    5      6
2    Gonza    8      9
3    Elton    6      1    

(lets call PrincipalArray this data)

I have this array in a Google Sheet. I get this values to a 2 dimensional array in JavaScript in Google Apps Script.

Then i want to filter something like: "Number of row who have the name Elton and the ID is 6" --> output is "row 3"

I need this because i need to edit this row when the criteria is true and i need to know the number of row. And if does not exist something with this criteria i need an answer like "-1.00" when indexof can not find something.

I will repeat this search many times, i mean, i need this automated.

I was thinking in something similar like IndexOf but i can just IndexOf first column for Elton and does not exists and "indexOf with two criteria".

In pseudo-code i think this too:

1. Get first column with names (new 1 dimension array "NamesArray")
2. Get 2th column with IDs (new 1 dimension array "IDsArray")
3. Filter Array to know how much Eltons are in the array (length of my For Loop)
4. Loop for with "how much eltons are in array" as length
5. Make indexof in First Column for "elton" ( NamesArray.indexOf("Elton")
6. Use the result of Indexof in Elton to verify if the 2th column have that ID in that row
7. iterate..

 function asdasdasd() { //My data in google sheets var PrincipalArray = [ [ "Name", "IDs", "Date"], [ "Jhon", 2, 3 ], ["Elton", 5, 6 ], ["Gonza", 8, 9 ], ["Elton", 6, 1 ], ]; //My first criteria to search var NameToSearch = "Elton"; //will be an input variable by human var IDsToSearch = "6"; //will be an input variable by human //Name Get columns from 2 dimentional array because IndexOf only works in 1 dimentional array var getColumns = (arr, indices) => arr.map(row => indices.map(i => row[i])); var PrincipalArray_Col_Name_2darr = getColumns(PrincipalArray, [0]); var PrincipalArray_Col_Name = PrincipalArray_Col_Name_2darr.map( function(r) {return r[0];}); //IDs Get columns from 2 dimentional array because IndexOf only works in 1 dimentional array var getColumns = (arr, indices) => arr.map(row => indices.map(i => row[i])); var PrincipalArray_Col_IDs_2darr = getColumns(PrincipalArray, [1]); var PrincipalArray_Col_IDs = PrincipalArray_Col_IDs_2darr.map( function(r) {return r[0];}); //Filter the principal array then i can notice how much "Elton" there are var PrincipalArray_OnlyName = PrincipalArray.filter(function(item){ return (item[0] == NameToSearch); } ); //output expected is 2 rows with Elton Data //i will start the loop in the faster position var positionNow = PrincipalArray_Col_Name.indexOf(NameToSearch); //output expected is 2, the first appear of Elton //I will loop across the PrincipalArray but i will use IndexOf to go faster for ( var i=positionNow; i<PrincipalArray_OnlyName.length; i++) { //if is equal to "6" the ID of Elton if ( PrincipalArray_Col_IDs[positionNow] == IDsToSearch ){ //i will edit that ID and run something here becuase is a match Logger.log(PrincipalArray_Col_IDs[positionNow]); break; //break because i found the ID with Elton, i edited that and is enough no more things to do and i want go outside of the loop for } var positionNow = PrincipalArray_Col_Name.indexOf(NameToSearch,positionNow); //output expected is 4 now becuase i am making an indexof starting in the previous step and i will find the next match of "elton" if ( positionNow == PrincipalArray_OnlyName.length ) { //here i will edit something becuase the ID was not found and i need to know that. } } }

Answer 1

Use findIndex()

 //My data in google sheets var PrincipalArray = [ [ "Name", "IDs", "Date"], [ "Jhon", 2, 3 ], ["Elton", 5, 6 ], ["Gonza", 8, 9 ], ["Elton", 6, 1 ] ]; //My first criteria to search var NameToSearch = "Elton"; //will be an input variable by human var IDsToSearch = "6"; //will be an input variable by human const target_row = PrincipalArray.findIndex(row => row[0] == NameToSearch && row[1] == IDsToSearch) + 1; console.log(target_row);

Answer 2

Use .findIndex() :

 /*<ignore>*/console.config({maximize:true,timeStamps:false,autoScroll:false});/*</ignore>*/ const principalArray = [ [ "Name", "IDs", "Date"], [ "Jhon", 2, 3 ], ["Elton", 5, 6 ], ["Gonza", 8, 9 ], ["Elton", 6, 1 ] ]; const find = (sKey,sID) => principalArray.findIndex(row => row[0]===sKey && row[1] === sID) console.log(find('Elton', 6)) console.log(find('Elton',10)) console.log(find('Gonza',8))

 <:-- https.//meta.stackoverflow:com/a/375985/ --> <script src="https.//gh-canon.github.io/stack-snippet-console/console.min.js"></script>

Or as a simple loop:

 /*<ignore>*/console.config({maximize:true,timeStamps:false,autoScroll:false});/*</ignore>*/ const principalArray = [ ['Name', 'IDs', 'Date'], ['Jhon', 2, 3], ['Elton', 5, 6], ['Gonza', 8, 9], ['Elton', 6, 1], ]; const find = (sKey, sID) => { for ( let i = 0, row = principalArray[i]; i < principalArray.length; row = principalArray[++i] ) { if (row[0] === sKey && row[1] === sID) return i; } return -1; }; console.log(find('Elton', 6)); console.log(find('Elton', 10)); console.log(find('Gonza', 8));

 <:-- https.//meta.stackoverflow:com/a/375985/ --> <script src="https.//gh-canon.github.io/stack-snippet-console/console.min.js"></script>