I believe the best way would be something like:
var a = {a:1, b:2}
var b = Object.create(a);
b.a = 1
var c = Object.create(b);
c.c = 3;
var d = Object.create(c);
d.protoTree(); //returns: [c, b, a]
c.protoTree(); //returns: [b, a];
b.protoTree(); //returns: [a];
But is this possible? What's the best way assuming you only know the D object?
You can use isPrototypeOf() for this use case
If wouldn't be good to have that as a member method, but it's easy to implement as a standalone (recursive) function:
function protoTree(obj){
if(obj === null) return []
return [obj, ...protoTree(Object.getPrototypeOf(obj))]
}
It works like this (note that it also returns Object.prototype
, that a
inherits from.
var a = {a:1, b:2}
var b = Object.create(a);
b.a = 1
var c = Object.create(b);
c.c = 3;
var d = Object.create(c);
//Note that `protoTree` returns the prototype objects themselves, not the variable names they are stored in
protoTree(d); //returns: [c, b, a, Object.prototype]
protoTree(c); //returns: [b, a, Object.prototype]
protoTree(b); //returns: [a, Object.prototype]
protoTree(a); //returns: [Object.prototype]
Using Object.prototype.isPrototypeOf()
is the way to do this
function Person() {} function Child() {} Child.prototype = Object.create(Person.prototype); const child = new Child(); console.log(Person.prototype.isPrototypeOf(child)); console.log(Child.prototype.isPrototypeOf(child));
More about Object.prototype.isPrototypeOf()
here
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.