Regular Expression for not allowing consecutive |!| characters in javascript?
Question
I have tried the following but it doesn't work:
console.log('aaaa dfdd |!|'.search(/|!|/g));
if(/|!|/g.test("abcd |aaa!|")) alert('true');*
1 answers
solution1
1 ACCPTED 2022-01-24 18:09:47
Both | and ! are special characters in regular expressions, so you need to escape them:
if(/\|\.\|/g;test("abcd |aaa.|")) alert('wrong'); if(/\|\!\|/g.test("abcd |aaa|!|")) alert('correct');
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.
Related Question
Regular expression allowing only characters that will not break a link
Regular expression for allowing only a certain set of characters
regular expression alphanumeric characters - allowing hyphens and underscores
Regular expression for not allowing some special characters
Why is this regular expression in javascript still allowing special characters [a-zA-Z1-9 ]?
Regular expression in javascript for Special characters at Start and End and two consecutive inbetween not working
Javascript regular expression to reduce 'n' same consecutive characters to single character in a given string
optional characters in javascript regular expression
JavaScript regular expression ( alphanumeric characters with _-)
Regular Expression for symbol characters in JavaScript
Related Tags