How to install multiple .deb files but in specific order with single linux command

Question

I have 4 debian installer:

abc.deb
jkl.deb
pqr.deb
xyz.deb

I want to install jkl and xyz first, and then I want to install abc.deb and pqr.deb . So the sequence/order the.deb files should be installed should be: jkl.deb , xyz.deb , abc.deb , pqr.deb .

PS:

1. When I am trying to run apt-get install./*.deb it is picking the.deb files in random (or maybe alphabetically) order.
2. So I did apt-get install./jkl.deb./xyz.deb./abc.deb./pqr.deb but still I am seeing that pqr.deb is Setting up first before abc.deb

Can someone let me know how can i install these four deb in specific order by single linux command?

Answer 1

As far as I know, the installation of packages follows an alphabetical order along with dependencies. So, if you try to install package X and Y but they have A and B as dependencies, the installation order would be: A, B, X and Y. In your case, you might have to use the following syntax:

apt install X && apt install Y

Answer 2

Try

apt-get install ./jkl.deb && apt-get install ./xyz.deb && apt-get install ./xyz.deb && apt-get install ./pqr.deb

Answer 3

*Put \n for new lines (so '\n' between each deb file)

list=$(echo -e "abc.deb\njkl.deb\npqr.deb\nxyz.deb")
for i in $list; do apt-get install ./$i; done

*or if you use gdebi

list=$(echo -e "abc.deb\njkl.deb\npqr.deb\nxyz.deb")
for i in $list; do sudo gdebi $i --n; done