JPA Query in inheritance tables

Question

i'm new on JPA, i need some help with a query that i would like to make.

This are my entities:

Service Entity

@Entity
@Table(name = "service", schema = "db2")
@Inheritance(strategy = InheritanceType.SINGLE_TABLE)
@DiscriminatorColumn(name = "serviceType")
public abstract class Service implements Serializable {
    private static final long serialVersionUID = 1L;
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private int idService;
    @ManyToMany
    @JoinTable(name = "pack-serv", schema = "db2", joinColumns = @JoinColumn(name = "idService"), inverseJoinColumns = @JoinColumn(name = "idPackage"))
    private List<Package> packages;

    public Service() {
    }
    //getter and setter of all attributes
}

Fixed Inte.net entity

@Entity
@Table(name = "service", schema = "db2")
@DiscriminatorValue("Fixed Internet")
public class FixedInternet extends Service implements Serializable  {
    private static final long serialVersionUID = 1L;
    
    private int GB;
    private int feeExtraGB;
    @Column(name="serviceType", insertable = false, updatable = false)
    protected String type;
    
    public FixedInternet() {
        super();
    }
     //getter and setter of all attributes
}

I would like to retrieve all FixedInte.net services that are related to a specific package ID. I made this query:

@NamedQuery(name = "FixedInternet.findServicesByPackID", query = "SELECT s.GB, s.feeExtraGB, s.idService FROM FixedInternet s JOIN s.packages p WHERE p.idPackage = ?1 AND s.type LIKE 'Fixed Internet'")

but when i run it an error shows up related to SQL syntax:

Internal Exception: java.sql.SQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '-serv t2, db2.package t1 WHERE ((((t1.IDPACKAGE = 1) AND t0.serviceType LIKE 'Fi' at line 1
Error Code: 1064
Call: SELECT t0.GB, t0.FEEEXTRAGB, t0.IDSERVICE FROM db2.service t0, db2.pack-serv t2, db2.package t1 WHERE ((((t1.IDPACKAGE = ?) AND t0.serviceType LIKE ?) AND (t0.serviceType = ?)) AND ((t2.idService = t0.IDSERVICE) AND (t1.IDPACKAGE = t2.idPackage)))
    bind => [3 parameters bound]

I can't resolve it, someone can help me to understand what i'm wrong?

This is the ER Diagram of the database if it could help: ER Diagram

UPDATE : without the part of "s.type LIKE 'Fixed Inte.net'", the error is pretty the same:

Internal Exception: java.sql.SQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '-serv t2, db2.package t1 WHERE ((((t1.IDPACKAGE = 1) AND t0.serviceType LIKE 'Fi' at line 1
Error Code: 1064
Call: SELECT t0.GB, t0.FEEEXTRAGB, t0.IDSERVICE FROM db2.service t0, db2.pack-serv t2, db2.package t1 WHERE (((t1.IDPACKAGE = ?) AND (t0.serviceType = ?)) AND ((t2.idService = t0.IDSERVICE) AND (t1.IDPACKAGE = t2.idPackage)))
    bind => [2 parameters bound]

Answer 1

I had the same error when I tried to CREATE a Table.

Internal Exception: java.sql.SQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'ORDER (ID BIGINT AUTO_INCREMENT NOT NULL, DATE DATE, ORDERTYPE INTEGER, VERSION ' at line 1

Error Code: 1064

Call: CREATE TABLE ORDER (ID BIGINT AUTO_INCREMENT NOT NULL, DATE DATE, ORDERTYPE INTEGER, VERSION INTEGER, CUSTOMER_ID BIGINT, PRIMARY KEY (ID))

The problem was that I was using a word reserved for MySQL (ORDER) to name the Table. The solution was to change the Table name to other.

If this helps...