My current solution is for x=3
a = "first one is"
b = "the second forever"
def fun(input):
if input.split()[-1] < 3:
return ' '.join( input.split()[0:-1])
else:
return input
fun(a)
"first one"
fun(b)
"The second forever"
Is there something more computationally efficient?
You can try this:
def fun2(input):
s = input.rsplit(' ', 1)
return s[0] if len(s[1]) < 3 else input
Time profiling using %timeit
:
In [25]: def fun(input):
...: if len(input.split()[-1]) < 3:
...: return ' '.join( input.split()[0:-1])
...: else:
...: return input
...:
In [26]: def fun2(input):
...: s = input.rsplit(' ', 1)
...: return s[0] if len(s[1]) < 3 else input
...:
In [28]: fun(a), fun2(a)
Out[28]: ('first one', 'first one')
In [29]: %timeit fun(a)
433 ns ± 0.759 ns per loop (mean ± std. dev. of 7 runs, 1,000,000 loops each)
In [30]: %timeit fun2(a)
222 ns ± 1.04 ns per loop (mean ± std. dev. of 7 runs, 1,000,000 loops each)
fun2
is faster because rsplit
is slightly faster and it avoids redundant computation.
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.