While I had received some great feedback on my previous post, I believe that my original question was not entirely clear and hence the answers did not generate the desired outcome.
I have a long vector of a character variable strings with about 600K observations having 800 unique string values. I am trying to narrow down these 800 unique strings to about 20 unique strings based on another vector of important string variables.
Here is an example:
col1 <- c("CORE_I5-xxxx_6C_VPRO", "A6-xxxx_MB", "CORE_I7-xxxx_4C_VPRO_MB", "INTEL_CORE_I3_MB", NA)
col2 <- c("CORE_I5_VPRO", NA, "CORE_I7_VPRO", "INTEL_CORE_I3", NA)
The new column (col2) has been created from the old column (col1) based on the following character variable (V) only by retaining the strings included in V:
V <- c("CORE", "INTEL", "I5", "I7", "I3", NA)
I have tried the following code but it is only giving me part of the strings, but not all the elements in each observation.
library(stringr)
col2 <- str_extract(col1, paste(V, collapse="|"))
I have also tried the suggestions to my previous post but unfortunately I am not getting the desired output. Thank you all for the help
Here we create x
and then use grepl
:
library(stringr)
x <- str_replace_all(str_remove(S, '(\\d+\\_)'), '\\_', '')
x[grepl(paste0(V, collapse = "|"), x)]
[1] "INTELI5VPRO" "COREdfds" "VPROLI9"
You can do follow your original approach, but using str_extract_all
and sapply()
, like this:
sapply(str_extract_all(S, paste(V, collapse = "|")),paste0, collapse="")
Output
[1] "INTELI5VPRO" "CORE" "" "VPROI9" "NA"
Or, you can do something like this:
lapply(S, \(s) {
x = strsplit(s, "_")[[1]]
result = paste0(x[x %in% V], collapse="")
ifelse(result=="", as.character(NA),result)
}) %>% unlist()
Output
[1] "INTELI5VPRO" "CORE" NA "I9" NA
str_extract_all
gives you a matrix of hits. Concatenating the strings of each row almost gives you your desired result. Only the third item is ""
instead of NA
.
library(stringr)
S = c('123_INTEL_I5_VPRO', '531_CORE_dfds', '93_RAYZEN_29dad', '452_VPROL_I9', NA)
V = c('INTEL','CORE', 'VPRO', 'I5', 'I9')
matches <- sapply(V, function (x) str_extract_all(S, x))
result <- apply(matches, 1, function(x) str_flatten(unlist(x))) # concatenate rows
result[result == ""] <- NA
result
#> [1] "INTELVPROI5" "CORE" NA "VPROI9" NA
Created on 2022-06-30 by the reprex package (v2.0.1)
You'd want to use str_extract_all
and take care of the empty extractions like the one in position 3 (based on your code):
sapply(str_extract_all(S, paste(V, collapse = "|")),
function(x) ifelse(length(x) != 0, str_flatten(x), NA)
)
#> [1] "INTELI5VPRO" "CORE" NA "VPROI9" NA
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