List comprehension on nested for loop

Question

I have a list:

l1 = [1,2,3,6,8,1,2,3]

I want to iterate over list and print list of numbers starting and ending with same number.I have done it with for loop:

iniatializing = 1
for i in l1:
 for j in range(iniatializing,len(l1)):
     if i == l1[j]:
         starting_point =l1.index(i)
         print(l1[starting_point:j+1])
     iniatializing += 1

But how can this be done by using list comprehension?

Answer 1

I suppose what you want to achieve is:

For each i , j ( i < j ), if l1[i]==l2[j] , print the subset between i and j .

n = len(l1)
[l1[i:j+1] for i in range(n) for j in range(i+1, n) if l1[i] == l1[j]]

EDIT: answer to the question about the original implementation.

l1 = [1,2,3,6,8,1,2,3]

iniatializing = 1
for i in l1:
 for j in range(iniatializing,len(l1)):
     if i == l1[j]:
         starting_point =l1.index(i)
         print(l1[starting_point:j+1])
 iniatializing += 1

#[1, 2, 3, 6, 8, 1]
#[2, 3, 6, 8, 1, 2]
#[3, 6, 8, 1, 2, 3]