How to correctly pass a dynamic value in a SQL query in PHP

Question

I have just started working on PHP and I am currently working on a simfony project. I have a query that inserts correctly a row in a table and then I need to retrieve the id of that row and use it to insert other values in another table. The problem is that I do not know how pass dynamic values in a sql query in php.

This is the query I wrote and the value in gridConfigId must be dynamic butof course just by passing it as $recordId is not working.

    $recordId = $this->addSql('SELECT id FROM gridconfigs ORDER BY creationDate DESC LIMIT 1');

    $this->addSql("  INSERT INTO `gridconfig_favourites` (`ownerId`, `classId`, `objectId`, `gridConfigId`, `searchType`, `type`) VALUES
    (12,    'EF_OSO',   0,  $recordId,  'folder',   'object'),
    (12,    'EF_OSO',   624,    $recordId,  'folder',   'object');");

What is the right syntax?

Answer 1

尝试使用：

 $recordId = $this->connection->fetchColumn('SELECT id FROM gridconfigs ORDER BY creationDate DESC LIMIT 1');