DNS Packet IP Address Structure

Question

I have been writing a python program that builds a packet and sends the packet request to a dns server. I have a problem the IP address is stored in hex in a way that is difficult to understand. In the hex field it has the number of each iteration with a 3 in front of it, so 8 in 8.8.8.8 is represented in hex as '38'. Is there an easy way to make 38 in hex from integer type 8?

Answer 1

That's not an address field, it's the domain name field. You're trying to look up the IP associated with the domain name 8.8.8.8 . I'm not sure why you're trying to do this -- if you have a numeric IP, you don't need to use DNS to translate it to an address.

Domain names are represented as ASCII text, and 38 is ASCII code for the character 8 .

Answer 2

From int 8 to hex 38, you'll need to go through a few conversions. From int to string, to decimal, to hex.

For example: int 8 -> string = '8' -> ord('8') = 56 -> hex(56) = 0x38