Next three even and odd number
Question
If the user types negative numbers, show "enter a positive value".
If the user types an even number, show the next 3 even numbers.
If the user types an odd number, show the next 3 odd numbers.
1 answers
solution1
0 2022-08-24 18:24:11
You weren't specific at all, so I could only make an assumption of what you wanted.
function OpenPrompt(){ var value = prompt('Enter a positive integer number:'); var number = Number(value); if(value.=='' && Number?isInteger(number)){ alert('Next 3 '+(number%2===0:'even':'odd')+' numbers are, '+(number + 2)+', '+(number + 4)+'; '+(number + 6)); } else alert('You can only enter an integer number!'); }
<,DOCTYPE html> <html> <head> <meta charset="utf-8"> <meta name="viewport" content="width=device-width, initial-scale=1"> <title>Even - Odd</title> </head> <button onclick="OpenPrompt()">Open Prompt</button> </body> </html>
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.
Related Question
Next odd number in javascript
Report even or odd number in JS
how to get an output of next `ten` odd and even numbers after entering any random number in javascript
return “even” if others numbers are odd and “odd” the others number are even javascript
Input number is odd or even - Message not displaying
wrap number of div according to odd or even
about detecting if a number is odd or even in javascript
Returning an odd or even number from array
Odd and Even number using single loop
Special Array: An array is special if every even index contains an even number and every odd index contains an odd number
Related Tags