how to get an output of next `ten` odd and even numbers after entering any random number in javascript

Question

I want to have a logic where if I enter an even number I want next 10 even numbers to be printed and If I enter an odd number, I want next 10 odd numbers to be printed. How should I rectify this logic inside a function. If someone can please help me rectifying the logic which was answered.

JS

 function oddEven() { var input = prompt(""); for (let x = 1; x <= 10; x++) { console.log(input + x * 2); } } oddEven()

Answer 1

This should work for any number

const input = 2
for (let x = 1; x <= 10; x += 1) {
 console.log(input + x * 2)
}

Answer 2

 let inputval = 2; for (let x = 1; x <= 10; x++) { console.log(inputval + x * 2) }

Answer 3

i hope this help

function printTen(input){
  let list = []
  let number = input
  while(list.length <= 10){
    number++
    if(input % 2 === 0 && number % 2 === 0){
      console.log(number +  " is even");
      list.push(number)
    }else if(input % 2 !== 0 && number % 2 !== 0) {
      console.log(number +  " is odd");
      list.push(number)
      
    }
  }
}

printTen(9)