How do I check whether comma separated elements of a string are in the list or not?

Question

a = "3"
b = ["3"]

def func():
    return a in b

The above function returns "TRUE"

But if I have my code as follows:

a="1,2,3,4"
b = ["3"]

How do I check the elements of a one by one with b, ie, "1"==["3"] or "2"==["3"], and so on, and return "TRUE" when "3"==["3"]

Answer 1

Try this

a="1,2,3,4"
b = ["3"]


def func(a,b):
    return any(e in b for e in a.split(','))

print(func(a,b))

Output

True

---

• Usesplit(',') for converting string to list.
• Code inside the any() function e in b for e in a.split(',') returns a list of True and False based on condition, Here e values are 1 , 2 , 3 , 4 one by one and check if e is in b list.
• Use the any() function, It returns True if one of the conditions is True in the list.

Answer 2

It's simple.Try this:

a="1,2,3,4"
b = ["3"]
a_list = a.split(',')
for i in a_list:
    if i in b:
        print("True")
        break

Output:

True

Answer 3

I guess you're using Python. You can use the Python 'split' method on 'a' to create a new list that contains elements separated by ',', like this:

new_list=a.split(',')

Now you can use a for loop to go through 'new_list' and check if any element equals 'b'.

Answer 4

def get_list_from_file(filename):
    with open(filename, 'r') as f:
        contents = f.read()
    return contents.split(',')

def search_list(contents, value):
    if value in contents:
        return True
    else:
        return False
contents = get_list_from_file('test.csv')
value = input('Enter a value to search for: ')
if search_list(contents, value):
    print('Found')
else:
    print('Not found')

Answer 5

1. You can use the split method to convert string to array

2. Compare your value with the array.

   arr = "1,2,3,4" b = ["3"]

   def find(): return b[0] in x

   x = arr.split(',') x = find()

   print(x)