Function that takes a string text and positive integer and converts it to list of words

Question

Stuck on the question "Write a function repeat_word_count(text, n) that takes a string text and a positive integer n, converts text into a list of words based on simple whitespace separation (with no removal of punctuation or changing of case), and returns a sorted list of words that occur n or more times in text. Eg repeat_word_count("wings wings wings wings", 2) -> output is ['wings'] So far I have got:

def repeat_word_count(text, n):
    tally = {}
    for char in repeat_word_count:
        if char in tally:
            tally[char] += 1
        else:
            tally[char] = 1
        if tally[char] >= n :
            print(tally.sorted())

I wanted to end with 'return tally' but I kept getting indent errors. But in general, I am getting the error TypeError: 'function' object is not iterable which I don't understand, if someone could explain that too it would help tons!

Answer 1

def repeat_word_count(text, n):
    #split string by " " into a list of words
    words = text.split(" ")

    words_iterator={}
    #interate throught the words
    for word in words:
        #if word is in the keys add 1 to his count 
        if word in words_iterator.keys():
            words_iterator[word]+=1
        #else add the word as a key and the counter as 1 giving is 
        #the first time the word appeard in the list
        else:
            words_iterator[word] = 1

    output=[]
    #parse the dict key by key 
    for key in words_iterator:
        # if the value of the key is bigger than n add key to list 
        if words_iterator[key]>=n:
            output.append(key)

    return output

Output