Turn List of Dictionaries into Dictionary of Dictionaries with index

Question

I have a list of dictionaries, like this:

ls_dict = [{'py': 'Python', 'mat': 'MATLAB', 'cs': 'Csharp'}, 
{'A': 65, 'B': 66, 'C': 67}, 
{'a': 97, 'b': 98, 'c': 99}]

Which produces this:

[{'py': 'Python', 'mat': 'MATLAB', 'cs': 'Csharp'}, {'A': 65, 'B': 66, 'C': 67}, {'a': 97, 'b': 98, 'c': 99}]

What I want is a dictionary of dictionaries where each dictionary is indexed like the following:

{"0": {'py': 'Python', 'mat': 'MATLAB', 'cs': 'Csharp'}, "1": {'A': 65, 'B': 66, 'C': 67}, 2: {'a': 97, 'b': 98, 'c': 99}}

The additional problem is that I need to convert the former to the latter, rather than adapting my sample creation code, as I just spent 15 hours downloading the data into the current (wrong) format.

Any suggestions? Thank you.

Answer 1

You can do with enumerate ,

In [75]: {str(index): lst for index, lst in enumerate(ls_dict)}
Out[75]: 
{'0': {'py': 'Python', 'mat': 'MATLAB', 'cs': 'Csharp'},
 '1': {'A': 65, 'B': 66, 'C': 67},
 '2': {'a': 97, 'b': 98, 'c': 99}}

Answer 2

hello you need to do this whit for

keyList = ['0','1','2']
valueList = [{'py': 'Python', 'mat': 'MATLAB', 'cs': 'Csharp'}, {'A': 65, 'B': 66, 'C': 67}, {'a': 97, 'b': 98, 'c': 99}]
d = {}
for i in range(len(keyList)):
    d[keyList[i]] = valueList[i]
print(d)