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Remove empty dictionary(nested) from list Python

data = [
    {
        "2022": [
            {
                "Title": "Title"
            },
            {
                "Title": "Title 2"
            }
        ]
    },
    {
        "2023": []
    },
    {
        "2024": []
    }
]

Now I want to remove 2023 and 2024 because it do not have any value. Solution in python:

for el in data:
    for dict in el.values():
        if len(dict) == 0:
            data.remove(el)

Similar Solution in JS:

data = data.filter(item=>Object.values(item)[0].length > 0)

What i want is similar to js. (I am not an expert in python)

Solution in one line:

    data = [
        {
            "2022": [
                {
                    "Title": "Title"
                },
                {
                    "Title": "Title 2"
                }
            ]
        },
        {
            "2023": []
        },
        {
            "2024": []
        }
    ]
    result = [{k: v} for el in data for k, v in el.items() if len(v) > 0]

Output:

[{'2022': [{'Title': 'Title'}, {'Title': 'Title 2'}]}]

You can use this:

data = [
    {
        "2022": [
            {
                "Title": "Title"
            },
            {
                "Title": "Title 2"
            }
        ]
    },
    {
        "2023": []
    },
    {
        "2024": []
    }
]

data = [k  for k in data for key in k.keys() if k[key]!=[]]

Output:

[{'2022': [{'Title': 'Title'}, {'Title': 'Title 2'}]}]

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