How to output an element (content of index) that has been repeated by the user input multiple times with out using the collections, hashmap or treemap method?
I am looking for a linear or you could say a mathematical approach rather than a ready command approach, could someone help please?
import java.util.ArrayList;
import java.util.Scanner;
Scanner scanner = new Scanner(System.in);
ArrayList<Integer> arrayList = new ArrayList<>();
while (true) {
int input = scanner.nextInt();
if (input == -1) {
break;
}
arrayList.add(input);
}
System.out.println("search for? ");
for (int loopValue = 0; loopValue < arrayList.size(); loopValue++) {
int input2 = scanner.nextInt();
System.out.println(input2 + " is at index " + arrayList.indexOf(input2));
}
/ a sample output should look similar to the following:
input user:
10
20
20
30
30
40
50
if -1 is inputted, the user will exit the loop
Number you are searching for in an array list?: the user again input the desired number 30
number 30 is at index 3
number 30 is at index 4
how can I show the indices of a frequent number just like above^?
If I understand your question correctly you could do:
System.out.println("search for? ");
int input2 = scanner.nextInt();
for(int i =0; i<arrayList.size();i++){
if(arrayList.get(i)==input2){
System.out.println(input2 + " is at index " + i); //e.g. 30 is at index 3
}
}
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