SQL - How To Count Certain Char in Row

Question

I have a column called colors that lists some colors, separated by semicolon.

I want to include in my select statement, a way to create a column that counts the semicolon for each respective row.

Here is sample output

Assume the only column we have to work with is Colors from table called SampleTable

Answer 1

try this query

select Colors, LENGTH(Colors)- LENGTH(REPLACE(Colors, ';', '')) as CountSemiColon  from table_name

Answer 2

You can count only sign ; with this example, here find count sign l

select host, (CHAR_LENGTH(host) - CHAR_LENGTH(REPLACE(host, 'l', ''))) / CHAR_LENGTH('l') AS cnt from user;
+-----------+--------+
| host      | cnt    |
+-----------+--------+
| 127.0.0.1 | 0.0000 |
| honeypot  | 0.0000 |
| honeypot  | 0.0000 |
| localhost | 2.0000 |
| localhost | 2.0000 |
+-----------+--------+
5 rows in set (0.00 sec)

Example find in this answer

Answer 3

Try this:

SELECT colors,
   ROUND ((LENGTH(colors) - LENGTH(REPLACE(colors, ';', ''))) / LENGTH(';')) 
   AS char_count 
   FROM table_name

Answer 4

You can use IF to handle the null (count = 0) case as well.

select Colors, IF (Colors IS NULL, 0, LENGTH(Colors) - LENGTH(REPLACE(Colors, ';', ''))) as CountSemiColon from SampleTable;