I want to use a counter to find the original number that the user entered, but I can't figure out how

Question

#include <iostream>
using namespace std;

const int MAX_SIZE  =100;
int myArray [MAX_SIZE] = {};

int main(){
    int userInfo;
    cout << " enter a non 0 integer value" << endl;
    cin >> userInfo;
    myArray[0] = userInfo;
     
    int count;

    return 0;
}

I want to find the original value that was entered using a counter, ex:

5 6 7 4

The original array is:

5 6 7 4

Answer 1

If my understanding is correct and you are trying to keep counting until you find the number entered by the user, you can do the following loop:

#include <iostream>
using namespace std;

const int max = 100 //max value
int x;
cout << "Enter a positive value: ";
cin >> x;
for (int counter = 0; counter < max; counter++)
{
    if (counter == x)
    {
        cout << "The value you entered is: " << counter << endl;
        break; //exit the loop
    }
}
//you no longer need to use "return (0);" in current versions of c++

this code uses a for loop to keep counting till it finds the right value. You can also do the same thing using any looping mechanism like do while loops.