count the frequency and sort (in ascending order) values in "title" key from the dictionary nested in the list

Question

I need the following:

• highest frequency(ies) of the values of deet["title"]
• the list rearranged in terms of frequency(from highest to lowest)

deet = [{
  'title': 'T-90',
  'timestamp': '2022-10-08T21:01:51Z'},
 {
  'title': 'Category:17th-century women of the Ottoman Empire',
  'timestamp': '2022-10-08T21:01:50Z'},
{
  'title': 'T-90',
  'timestamp': '2022-10-08T21:01:51Z'},
{
  'title': 'T-90',
  'timestamp': '2022-10-08T21:01:51Z'},
{
  'title': 'T-91',
  'timestamp': '2022-10-08T21:01:51Z'}
]

from collections import Counter
print([new["title"] for new in deet].Counter())

this is a part of the data, deet but it is the same structure. i tried to use counter method from collections but i am really getting errors. i need the frequency of the values of title, that is how many times T-90 is in the list.

Answer 1

One way to do this is to use a defaultdict from the collections library to count the items. The defaultdict can then be sorted by item count using a lambda function which returns the value for each of the defaultdict's keys. Note that the flag reverse=True returns highest to lowest in this case.

from collections import defaultdict
dd = defaultdict(int)
for item in deet:
    dd[item.get('title')] += 1
sorted(dd, key=lambda k: dd[k], reverse=True)

Using Counter from the same collections library is also a good solution; in this case you need to get each item's title from each dict in the list.

from collections import Counter
Counter([item['title'] for item in deet])