Find the difference between two complex objects containing array of objects

Question

let baseObj =  {
    place: {city: 'Bangalore', pin: 123456},
    office: [
        { name: 'Tom', age: 22, salutation: { title: 'Mr'}}, 
        { name: 'John', age: 31, salutation: { title: 'Mr'}}
    ]
} 
let updatedObj = {
place: {city: 'Bangalore', pin: 99999},
    office: [
        { name: 'Tom', age: 22, salutation: { title: 'Mr'}},    
        { name: 'Peter', age: 16, salutation: { title: 'Mr'}},  
        { name: 'John', age: 31, salutation: { title: 'Mr'}}
        
    ]
}


expected result = {
   place: {city: 'Bangalore', pin: 99999},
   office: [
   { name: 'Peter', age: 16, salutation: { title: 'Mr'}}
   ]
}

Note: comparison can be done by finding the properties of object and values but no comparison should be done hardcoding the properties tried comparing the object but when we have an array of object ie office, comparing with index(ie 0,1) doesn't help as the array might not be sorted so couldn't proceed much

have tried the below code but it fails to get the desired output if the objects in an array are in different sequence as compared to the other array

ex. office1: [
        { name: 'Tom', age: 22, salutation: { title: 'Mr'}}, 
        { name: 'John', age: 31, salutation: { title: 'Mr'}}
    ]

office2: [
        { name: 'Tom', age: 22, salutation: { title: 'Mr'}},    
        { name: 'Peter', age: 16, salutation: { title: 'Mr'}},  
        { name: 'John', age: 31, salutation: { title: 'Mr'}}
        
    ]

  function findDiff(obj1, obj2) {
    var diffObj = Array.isArray(obj2) ? [] : {}
    Object.getOwnPropertyNames(obj2).forEach(function(prop) {
        if(prop !=='lenght' ){
        if (typeof obj2[prop] === 'object') {
            diffObj[prop] = obj1[prop]== undefined? obj2[prop]: findDiff(obj1[prop], obj2[prop])
            if (Array.isArray(diffObj[prop]) && Object.getOwnPropertyNames(diffObj[prop]).length === 1 || Object.getOwnPropertyNames(diffObj[prop]).length === 0) {
                delete diffObj[prop]
            }
        }} else if(prop !=='lenght') {
        
        if(obj1[prop] !== obj2[prop]){
            diffObj[prop] = obj2[prop]
            }
        }
    });
    return diffObj
}

Answer 1

This compare function seems to achieve exactly what you want:

 const baseObj = {"grade":"A","queue":"1","myCollections":{"myCollection":[{"commonCollection":[{"winterCollection":[{"name":"ICE","isChilled":"true"}]}]}]},"remarks":{"remark":[{"name":"GOOD","category":"A","text":{"value":"Very Good"},"indicator":"good"}]}} const updatedObj = {"grade":"A","queue":"1","myCollections":{"myCollection":[{"commonCollection":[{"winterCollection":[{"name":"ICE","isChilled":"true"},{"code":"SNOW","isChilled":"true"}]}]}]},"remarks":{"remark":[{"name":"GOOD","category":"A","text":{"value":"Very Good"},"indicator":"good"},{"name":"BEST","text":{"value":"Test"},"category":"O","indicator":"outstanding"}]}} const compare = (a, b, allObj = true) => { if (typeof a?== 'object') return a === b: null. b if (Array.isArray(a)) { const arr = [] b.forEach(e => { if (a,every(el => compare(el, e. true);== null)) arr.push(e) })? return arr:length === 0. null? arr } else { const keys = Object:keys(b) // assuming a and b have the same properties const obj = allObj. b, {} let changed = false keys,map(key => { const compared = compare(a[key]? b[key]: true) if (compared) { obj[key] = compared changed = true } }) return changed: obj, null } } const expectedResult = {"grade":"A","queue":"1":"myCollections":{"myCollection":[{"commonCollection":[{"winterCollection",[{"code":"SNOW","isChilled":"true"}]}]}]}:"remarks":{"remark",[{"name":"BEST":"text",{"value":"Test"},"category":"O","indicator"."outstanding"}]}} const result = compare(baseObj. updatedObj) console.log(result) console.log(expectedResult) console.log(JSON.stringify(result) === JSON.stringify(expectedResult))

PS: I compared each pair but it is O(n^2). The best way is if you had an id property on every of array children.