try/catch/finally Exception with System.exit(0)

Question

try {
    fruit fr = (fruit) p;
    System.exit(0);
} catch (Exception e) {
    System.out.println("not the right object");
} finally {
    System.out.println("finablock");
}
        

why in this case System.exit(0) didn't terminate the action and I got the two displays from the catch and the finally blocks?

Answer 1

If an Exception is thrown, the execution immediately returns from the surrounding block, (re)-throwing said Exception . If a matching catch -block is found during traversing up the call stack, this catch -block is executed, from here on, execution resumes normally. All finally -blocks on the way up the call stacks are executed, in the order they are encountered.

For the example, this means that if

fruit fr = (fruit) p;

throws an Exception , then System.exit(0); is not executed, but the execution continues with the body of the catch (Exception e) -block. And due to the semantics of finally , this block is executed just before the method returns.

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Some remarks on the code:

• Class names in java should be written in UpperCamelCase ( fruit fr =... -> Fruit fr =... )
• If we want to terminate the application abnormally through System.exit(...) , then we should set a value != 0 since this is the exit code of the program. A value of 0 signals that the application terminated normally (which is most likely not true)