Python code to unzip multiple zip files then rename extracted files

Question

I'm trying to find python script to extract 3 zip files in a folder then deleting the zip files and modifying the extracted files name. actually I need to take only first 80 characters from the name of each extracted file.

If anyone can help. thanks

I used below script

import zipfile,os,fnmatch, glob

path = "Directory\\"
dir_list = os.listdir(path)

counter = 1

for file in dir_list:
with zipfile.PyZipFile(path+"\\"+file,'r') as zObject:
    zObject.extractall(path=path)
zObject.close()
counter +=1
os.unlink(path +file)

os.chdir("Directory\\")
for file in os.listdir():
print(file)

I can see unzipping and zipfiles deletion done, but when I tried to rename the files I can see below error so I can't move to next step

File "C:\Users\melnagga\AppData\Local\Programs\Python\Python311\Lib\zipfile.py", line 1366, in _RealGetContents raise BadZipFile("File is not a zip file") zipfile.BadZipFile: File is not a zip file

Answer 1

The Key for me was to extract the zip files into other directory, then rename extracted files in the new directory

used code is as shown below:

import zipfile,os


path = "Directory_pth\\" 
dir_list = os.listdir(path)


for file in dir_list:
    with zipfile.PyZipFile(path+"\\"+file,'r') as zObject:
        zObject.extractall(New Directory_path")
    os.unlink(path +file)
    zObject.close()
    
os.chdir("New Directory_path")
for file in os.listdir():
   name, ext = os.path.splitext(file)
   splitted = name.split("-")
   new_name = f"{splitted[0]}_new{ext}"
   os.rename(file,new_name)

Thanks to everyone tried to help