<?php
function table() {
ot();
for($x=0; $x<$rows; $x++) {
table_row($x);
}
ct();
}
?>
Notice: Undefined variable: rows in .../scratch.php on line 12
Hi,
This function is returning an error because $rows is not defined locally. I define the variable $rows in another php script, which is referenced via "includes('includes.php')" at the top of this script file.
How do I pass or "reference" the variable $rows into this function? As you can tell, I'm still learning PHP and any help is greatly appreciated!
thx,
Define your function like this:
function table($rows) {
ot();
for($x=0; $x<$rows; $x++) {
table_row($x);
}
And then call it like this:
table($rows);
Where the $rows
variable is defined in your calling script.
The other option would be to make $rows
a global variable, in which case you can do:
function table() {
global $rows;
//etc
}
However, global variables should be avoided when possible, so I'd still recommend the first method.
if you want to use global variable withing the function you need to explicity declare it.
<?php
function table() {
global $rows;
for($x = 0; $x < $rows; $x++) {
table_row($x);
}
}
In most cases it is not a good idea to rely on globals and you should consider passing $rows
as a parameter.
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