简体   繁体   中英

SQL Server : How to treat nulls as zeros

Here is an example of what I'm trying to do:

Select
S1.Name as S1Name,
S1.Itemcontent as S1ItemContent,
...
S2.Name as S2Name,
S2.Name as S2ItemContent,
**(S1.OrderValue * 1000*1000 + S2.OrderValue*1000 +  S3.OrderValue) as OrderValue**
From (joining s1, s2 and s3 on a particular value)
Order by OrderValue

When S1.OrderValue, S2.OrderValue or S3.OrderValue is a null, then OrderValue becomes a null as well. I want SQL Server to treat nulls as a 0 in this case. How can i do this?

Using the isNull function, such as

isnull(s1.ordervalue,0)

If the value is null, it uses the alternative value you provided as the second value.

COALESCE (Value, 0)ISNULL (Value, 0)

Use T-SQL Coalesce to force a non-null answer. For example:

COALESCE(S1.OrderValue, 0)

...will take the OrderValue value unless it is NULL in which case 0 is taken.

Coalesce返回第一个非null值。

**(coalesce(S1.OrderValue,0) * 1000 + coalesce(S2.OrderValue,0)*1000 +  coalesce(S3.OrderValue,0)) as OrderValue

You could use a case statement.

SELECT title, price,
        Budget = CASE price
         WHEN price > 20.00 THEN 'Expensive'
          WHEN price BETWEEN 10.00 AND 19.99 THEN 'Moderate'
          WHEN price < 10.00 THEN 'Inexpensive'
          ELSE 'Unknown'
        END,
FROM titles

Returns the following:

Title                  Price       Budget
---------------------- ----------- ---------------
Cooking with Computers 11.95       Moderate
Straight Talk About Co 19.99       Moderate
The Busy Executive's D 19.99       Moderate
You Can Combat Compute 2.99        Inexpensive
Silicon Valley Gastron 19.99       Moderate
The Gourmet Microwave  2.99        Inexpensive
But Is It User Friendl 22.95       Expensive
Secrets of Silicon Val 20.00       Moderate
Net Etiquette          (null)      Unknown   

Example taken from here ( http://www.craigsmullins.com/ssu_0899.htm )

使用ISNULL(S1.ORDERVALUE,0)

The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM