简体   繁体   中英

C++: pass variable by value

This is the situation:

int f(int a){
    ...
    g(a);
    ...
}

void g(int a){...}

The problem is that the compiler says that there is no matching function for call to g(int&). It wants me to pass the variable by reference and g() recieves parameters by value.

How can I solve this?

Well, there's not much here, but the first thing is: make sure you have a declaration for g that's included before f is defined.

void g(int a);

Otherwise, when you get to f, function f has no idea what function g looks like, and you'll run into trouble. From what you've given so far, that's the best I can say.

您的函数g()需要在f()之上定义

There are two things wrong:

1) g is not declared before it is used, so the compiler will compain about that. Assuming you fixed that issue, then the next issue is:

2) f is not returning an int.

The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM