I have a field with a date/time value like this:
2009-11-17 18:40:05
It's in UTC. In the query how can I convert this to EST?
I'm trying something like this but it throws an error.
// datetime is the field name
SELECT
FROM_TZ(TIMESTAMP TO_DATE(datetime, 'yyyy-mm-dd hh24miss'), 'EST') AS DT
FROM
db_name
I had to tweak it slightly to get it to work on my database, but this worked:
select from_tz(to_timestamp('2009-11-17 18:40:05','yyyy-mm-dd hh24:mi:ss'), 'UTC')
at time zone 'America/New_York' from dual
The key is the "at time zone" syntax.
If you want to convert a date field from UTC to EST, this worked for me:
CAST(FROM_TZ(CAST(DATE_FIELD AS TIMESTAMP), 'UTC')
at time zone 'America/New_York' AS Date) as DESIRED_FIELD_NAME
First, I cast the desired date field (as DATE_FIELD) to a timestamp. The result of the cast is the first parameter of the FROM_TZ function, which requires the parameter to be of type TIMESTAMP. The second parameter is 'UTC', since that is what we are changing from.
Then, I cast the results of that function call back to type DATE and give it an alias.
select to_char(systimestamp at time zone 'EST','HH') EST_TIME,
TO_CHAR(SYSDATE,'HH') EDT_TIME,
NEW_TIME(SYSDATE,
(
CASE
WHEN to_char(systimestamp at time zone 'EST','HH') = TO_CHAR(SYSDATE,'HH')
THEN 'EST'
ELSE 'EDT'
END
),'GMT')
from dual
Try this in ORACLE, I am using 12.2.0.1.0 64bit
SELECT * FROM v$version; --find version information
SELECT SYSDATE UTC, NEW_TIME(SYSDATE, 'GMT', 'EST') EST FROM DUAL; --will give both zones
This worked for me, should work for you too.
An alternate approach to get the date and time can be,
from_tz(CAST(DATE_FIELD AS TIMESTAMP), 'UTC') at time zone 'America/New_York' as DESIRED_FIELD_NAME
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