Escaping sed strings correctly

Question

I have a regex and replacement pattern that have both been tested in Notepad++ on my input data and work correctly. When I put them into a sed expression, however, nothing gets matched.

Here is the sed command:

 # SEARCH = ([a-zA-Z0-9.]+) [0-9] (.*)
 # REPLACE = \2 (\1)

 sed -e 's/\([a-zA-Z0-9.]+\) [0-9] \(.*\)/\2 \(\1\)/g'

Here is a sampling of the data:

jdoe 1 Doe, John
jad 1 Doe, Jane
smith 2 Smith, Jon

and the desired output:

Doe, John  (jdoe)
Doe, Jane  (jad)
Smith, Jon (smith)

I have tried removing and adding escapes to different characters in the sed expression, but either get nothing matched or something along the lines of:

sed: -e expression #1, char 42: invalid reference \2 on `s' command's RHS

How can I get this escaped correctly?

Answer 1

我通常发现使用-r开关更容易，因为这意味着转义类似于大多数其他语言的转义：

sed -r 's/([a-zA-Z0-9.]+) [0-9] (.*)/\2 (\1)/g' file1.txt

Answer 2

A few warnings and additions to what everyone else has already said:

1. The -r option is a GNU extension to enable extended regular expressions. BSD derived sed's use -E instead.
2. Sed and Grep use Basic Regular Expressions
3. Awk uses Extended Regular Expressions
4. You should become comfortable with the POSIX specifications such as IEEE Std 1003.1 if you want to write portable scripts, makefiles, etc.

I would recommend rewriting the expression as

's/\([a-zA-Z0-9.]\{1,\}\) [0-9] \(.*\)/\2 (\1)/g'

which should do exactly what you want in any POSIX compliant sed . If you do indeed care about such things, consider defining the POSIXLY_CORRECT environment variable.

Answer 3

不使用-r开关时，需要转义加号。

Answer 4

Using awk is much simpler...:

cat test.txt | awk '{ print $3 " " $4 " " "("$1")" }'

Output:

Doe, John (jdoe)
Doe, Jane (jad)
Smith, Jon (smith)

See man awk 1

Answer 5

$ sed -e 's/\([a-zA-Z0-9.].*\) [0-9] \(.*\)/\2 \(\1\)/g' file
Doe, John (jdoe)
Doe, Jane (jad)
Smith, Jon (smith)