In Python, I've got a list of items like:
mylist = [a, a, a, a, b, b, b, d, d, d, c, c, e]
And I'd like to output something like:
a (4)
b (3)
d (3)
c (2)
e (1)
How can I output a count and leaderboard of items in a list? I'm not too bothered about efficiency, just any way that works :)
Thanks!
from collections import defaultdict
def leaders(xs, top=10):
counts = defaultdict(int)
for x in xs:
counts[x] += 1
return sorted(counts.items(), reverse=True, key=lambda tup: tup[1])[:top]
So this function uses a defaultdict
to count the number of each entry in our list. We then take each pair of the entry and its count and sort it in descending order according to the count. We then take the top
number of entries and return that.
So now we can say
>>> xs = list("jkl;fpfmklmcvuioqwerklmwqpmksdvjioh0-45mkofwk903rmiok0fmdfjsd")
>>> print leaders(xs)
[('k', 7), ('m', 7), ('f', 5), ('o', 4), ('0', 3), ('d', 3), ('i', 3), ('j', 3), ('l', 3), ('w', 3)]
A two-liner:
for count, elem in sorted(((mylist.count(e), e) for e in set(mylist)), reverse=True):
print '%s (%d)' % (elem, count)
I'm surprised that no one has mentioned collections.Counter
. Assuming
import collections
mylist = ['a', 'a', 'a', 'a', 'b', 'b', 'b', 'd', 'd', 'd', 'c', 'c', 'e']
it's just a one liner:
print(collections.Counter(mylist).most_common())
which will print:
[('a', 4), ('b', 3), ('d', 3), ('c', 2), ('e', 1)]
Note that Counter
is a subclass of dict
with some useful methods for counting objects. Refer to the documentation for more info.
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