jQuery gallery turn over with next and previous buttons
Question
i'm trying to do some kind of Gallery-Turn Over Script with jQuery. Therefor i got an array with - let's say 13 - images:
galleryImages = new Array(
'images/tb_01.jpg',
'images/tb_02.jpg',
'images/tb_03.jpg',
'images/tb_04.jpg',
'images/tb_05.jpg',
'images/tb_06.jpg',
'images/tb_07.jpg',
'images/tb_08.jpg',
'images/tb_09.jpg',
'images/tb_10.jpg',
'images/tb_11.jpg',
'images/tb_12.jpg',
'images/tb_13.jpg'
);
My gallery looks like a grid showing only 9 images at once. My current script already counts the number of li-elements in #gallery, loads the first 9 images and displays them. The HTML looks like this:
<ul id="gallery">
<li></li>
<li></li>
<li></li>
<li></li>
<li></li>
<li></li>
<li></li>
<li></li>
<li></li>
</ul>
<ul id="gallery-controls">
<li id="gallery-prev"><a href="#">Previous</a></li>
<li id="gallery-next"><a href="#">Next</a></li>
</ul>
I'm pretty new to jQuery an my problem is that i can't figure out how to split the array in portions with 9 elements to attach it as a link on the control buttons. I need something like this:
$('#gallery-next').click(function(){
$('ul#gallery li').children().remove();
$('ul#gallery li').each(function(index,el){
var img = new Image();
$(img).load(function () {
$(this).css('display','none');
$(el).append(this);
$(this).fadeIn();
}).attr('src', galleryImages[index]); //index for the next 9 images?!?!
});
});
Thanks for help!
3 answers
solution1
1 2010-04-26 18:21:22
Check out my solution to your problem .
A few important notes:
- I've changes the way your buttons work from a list to two spans.
- I moved the line
$(el).append(img)to a more appropriate spot. - The
curIndexis the index of the last most image. - To get the next index image, I used
curIndex+index, and then modded it by galleryImages.length so that it will loop the overflow rather than giving errors. - You cannot actually see the images (for obvious reasons), so I have added the index as text in each
<li>so you can see with is going on.
solution2
0 2010-04-26 18:20:29
You could create a variable, say var firstIndex = 0; to hold the array index of the first image currently displayed. Have your "next" button increment it and your "previous" button decrement it as necessary (by 1 or 9 or how you want). Add this value to index in your code.
Naturally you will need to check array bounds.
solution3
0 ACCPTED 2010-04-26 19:27:42
Try this:
<html>
<head>
<style>
#gallery-prev, #gallery-next{text-decoration:underline;color:Blue;cursor:pointer;list-style:none;display:inline;padding:5px;}
#gallery li{list-style:none;display:inline;}
</style>
<script type="text/javascript" src="jquery-1.4.2.min.js"></script>
<script type="text/javascript">
galleryImages = new Array(
'images/tb_01.jpg','images/tb_02.jpg','images/tb_03.jpg',
'images/tb_04.jpg','images/tb_05.jpg','images/tb_06.jpg',
'images/tb_07.jpg','images/tb_08.jpg','images/tb_09.jpg',
'images/tb_10.jpg','images/tb_11.jpg','images/tb_12.jpg',
'images/tb_13.jpg');
function loadImages(p) {
var startIndex = parseInt($('ul#gallery').attr("startIndex")) + 9 * p;
if (startIndex < 1 || startIndex >= galleryImages.length) return;
$('ul#gallery')
.attr('startIndex', startIndex)
.find("li").children().remove().end()
.each(function(i, el) {
var nextID = startIndex - 1 + i;
if (nextID >= 0 && nextID < galleryImages.length) {
$(this).append($("<img src='" + galleryImages[nextID] + "' alt='image " + (nextID + 1) + "' />"));
}
});
}
$(document).ready(function() {
$('ul#gallery').attr('startIndex', '1');
for (var i = 1; i <= 9; i++)
$('ul#gallery').append("<li></li>");
loadImages(0);
$('li#gallery-prev, li#gallery-next').each(function(i) {
$(this).click(function() {
loadImages(i == 1 ? 1 : -1);
})
});
});
</script>
</head>
<body>
<ul id="gallery"></ul>
<ul id="gallery-controls">
<li id="gallery-prev">Previous</li>
<li id="gallery-next">Next</li>
</ul>
</body>
</html>
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.