How can I remove these warnings?
char foo[10], msg2[100];
int k;
for (k = 0; foo[k] != NULL; k++) //comparison between pointer and integer
msg2[k] = NULL; //assignment makes integer from pointer without a cast
Thanks.
int k;
for (k = 0; foo[k] != '\0'; k++)
msg2[k] = '\0';
Assign an integer to an integer variable, instead of a pointer. NULL is a pointer. It is usually defined as:
((void *) 0)
The warning is right, your usage of NULL is wrong.
NULL was meant for pointers, not for string nul-terminator.
Use zero instead of NULL in your code, in BOTH places. If you want a special zero, you may use '\\0', but that;s redundant.
*foo = 0;
要“擦除”C样式字符串,您需要做的就是将第一个字节设置为0。
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