Split based by a-z character in an alphanumeric string in python

Question

我有类似“ 5d4h2s”的字符串，我想从该字符串中获取5、4和2，但我也想知道5与d配对，而4与h配对，依此类推。等等。一个简单的方法，而无需通过char解析char？

Answer 1

If your input does not get more complicated than 5d4h2s :

>>> import re
>>> s = "5d4h2s"
>>> p = re.compile("([0-9])([a-z])")
>>> for m in p.findall(s):
...   print m
... 
('5', 'd')
('4', 'h')
('2', 's')

And if it gets, you can easily adjust the regular expression, eg

>>> p = re.compile("([0-9]*)([a-z])")

to accept input like:

>>> s = "5d14h2s"

Finally, you can condense the regex to:

>>> p = re.compile("([\d]+)([dhms])")

Answer 2

For time string, you can try the following:

m = re.match("(\d+d)?(\d+h)?(\d+m)?(\d+s)?", "5d4h2s")
print m.group(1) # Days
print m.group(2) # Hours
print m.group(3) # Minutes
print m.group(4) # Seconds
print int(m.group(1)[:-1]) # Days, number