This is what i got now...
FolderBrowserDialog1.ShowDialog()
TextBox1.Text = FolderBrowserDialog1.SelectedPath
If FolderBrowserDialog1.SelectedPath = Nothing = True Then MsgBox("Select your folder..")
If FolderBrowserDialog1.SelectedPath = Nothing = True Then Button1.Enabled = False
If FolderBrowserDialog1.SelectedPath = Nothing = False Then Button1.Enabled = True
End Sub
FileOpen(1, ,,,,,, & "File" & ".dll", OpenMode.Output)
PrintLine(1, TextBox2.Text)
FileClose()
End Sub
But i want the Output folder (The place where File.dll is saved) to be the FolderBrowserDialog1.SelectedPath... how? Anyone?
Tried FileOpen(1, FolderBrowserDialog1.SelectedPath & File & .dll, OpenMode.Output) but no :(
请注意,我了解您要执行的操作,但是您可以尝试在调用ShowDialog方法之前设置SelectedPath属性。
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