meaning of 'operator' in this C++ statement

Question

“运算符”在这个C ++用法中意味着什么？

char* pszVar= W2A(_bstr_t(bstrVar).operator wchar_t*());

Answer 1

forcing the compiler to choose the, apparently defined, "convert to wchar_t*" operator in that class. "that class" being whatever is returned from the _bstr_t call.

Answer 2

That's an explicit call to the convertion operator to wchar_t , to be sure it's this one that will be used and not another.

That said, that's ugly and certainly show a problem in the class members.

Answer 3

它标记了对转换运算符的显式调用wchar_t* 。

Answer 4

它指的是铸造操作员。